A simple harmonic motion has an amplitude A and time period T. Find the time required by it to travel directly from
A
x = 0 to x = A/2
B
x = 0 to x = 
C
x = A to x = A/2
D
x = – 
to x = 
(e) x = 
to x = A.
to x = (e) x = to x = A.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
T/12, T/8, T/6, T/4, (e) T/8
Sol. x = A sin 
o = A sin 
⇒ 
o + ɸ = 0
⇒ ɸ = 0
x = A sin 
= A sin 
⇒ 
= 
t = 
x = A sin 
= A sin 
ɸ = 
x = A sin 
= A sin 
= 
⇒ t = 
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