Two particles P 1 and P 2 are performing SHM along the same line about the same mean position. Initially they are at their positive extreme positions. If the time period of each particle is 12 sec and the difference of their amplitudes is 12 cm then find the minimum time after which the separation between the particles become 6 cm.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(2s)
The coordinates of the particles are
x 1 = A 1 cos ω t, x 2 = A 2 cos ω t
separation = x 1 – x 2 = (A 1 – A 2 ) cos ω t = 12 cos ω t
Now x 1 – x 2 = 6 = 12 cos ω t
⇒ ω t = 
⇒ 
. t = 
⇒ t = 2s
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