Spring of spring constant k is attached with a block of mass m 1 as shown in figure. Another block of mass m 2 is placed against m 1 and both masses lie on smooth incline
(i) Find the compression in the spring when the system is in equilibrium.
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(i) At equilibrium position: →
Kx 0 = m 1 g sinθ + m 2 g sinθ
x 0 = 
Block will separate when acceleration of block of mass m 1 will be just equal to g sinθ
⇒ a = ꞷ 2 x = g sinθ
⇒ 
× x = g sinθ
⇒ 
g sinθ = x 0
So, blocks will separate when blocks are at distance x = 
g sinθ
(ii) From mean position
i.e. spring is at its natural position (amplitude A = 
)
Blocks will separate at distance x = x 0 from mean position.
v = 
= 
= 
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