Physics Electron, Photon, Photoelectric Effect and X-rays MHT CET Previous Year Question MCQ (Single Correct)

A metal surface is illuminated by light of given intensity and frequency to cause photoemission. If the intensity of illumination is reduced to one fourth of its original value then maximum K.E. of the emitted photoelectrons would be

A
twice the original value
B
four times the original value
C
one fourth of the original value
D
unchanged.

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The correct answer is:
D

As we know that the maximum kinetic energy of emitted photoelectrons does not depend on the intensity of illumination, only depends on the frequency of illuminated light. Thus, here when the intensity of illumination is reduced to one fourth of its original value then minimum kinetic energy will remain unchanged.

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