An engine pumps up 1000 kg of coal from a mine 100 m deep in 50 sec. The pump is running with diesel and efficiency of diesel engine is 25%. Then its power consumption will be (g = 10m/sec 2 ):
Text Solution
Verified by ExpertsThe correct answer is:
B
P = 
(mgh)
P act = 
P act = 20000 W
P consumption = 
W = 80 kW.
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