Two plates (area = S) charged to +q 1 and 
are brought closer to form a capacitor of capacitance C. The potential difference across the plates is:
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
A
Capacitance of the parallel plate capacitor is 
Where, A is area of plates and d is distance between them.
Potential difference across the plates,
Here, 
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