In the figure shown, 
(without dielectric) and 
(with a dielectric slab of dielectric constant 
). Now, the same slab after removing from C 2 is filled in C 1 . Then, match the following column-I and column-II.
Column-I | Column-II | ||
(A) | Charge on C2 | (I) | will increase |
(B) | Energy stored in C2 | (II) | will decrease |
(C) | Potential difference across C2 | (III) | will remain same |
(D) | Electric field between the plates of C2 | (IV) | data insufficient |
Text Solution
Verified by ExpertsA
Since, total capacity is decreasing. Hence, charge on both capacitors will decrease.
q has become 
or 0.8 times but C is halved. Hence, U 2 will increase.
q has become 0.8 times but C is halved. Hence, V 2 will increase.
or 
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