A bar magnet of magnetic moment 
aligned with direction of uniform magnetic field of 0.22 T.
Match the scenarios (Column A) with corresponding values (Column B).
Column I | Column II | ||
A. | Work required to align the magnetic moment normal to field direction | I. | 0.33 Nm |
B. | Work required to align the magnetic moment opposite to the field direction | II. | 0 |
C. | Torque on the magnet when the magnetic moment is normal to the field direction | III. | 0.66 J |
D. | Torque on the magnet when the magnetic moment opposite to field direction. | IV. | 0.33 J |
Choose the correct answer from the options given below.
Text Solution
Verified by ExpertsD
as the dipole is aligned with B.
When the bar magnet is displaced to perpendicular position, then 
.
When the magnet is displaced, so as to align M opposite to B, then
Let 
be the torque on the magnet when it is aligned perpendicular to B, then using the relation
Let 
be the torque on the magnet when the magnetic moment opposite to B, then
Hence, A-(IV), B-(III), C-(I), D-(II).
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems