A vertical conducting ring of radius R falls vertically with a speed v in a horizontal uniform magnetic field B which is perpendicular to the plane of the ring–
Text Solution
Verified by ExpertsB
When the ring falls vertically, there will be an induced emf across A and B [e = Bv (2r)] Note that there will be a potential difference across any two points on the ring, line joining whom has a projected length in the horizontal plane. For example, between points 'P' and 'Q' there is a projected length 'X' in the horizontal plane.
Potential difference across P and Q is:
V = B vx.
But for points C and D : x = 0
Therefore, Potential difference = O.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems