Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Match the following for single ionized helium atom (He + ) if total energy of electron in first orbit in H-atom is – 13.6 eV/atom.
Column I | Column II |
(i) P.E. of electron in ground state | [A] – 54.4 eV/atom |
(ii) K.E. of electron in ground state | [B] 13.6 eV/atom |
(iii) Total energy of electron in ground state | [C] – 108.8 eV/a |
(iv) Ionisation energy of He+ in lawest excited state | [D] 54.4 eV/atom |
Correct Matrix Matching
Text Solution
Verified by ExpertsThe correct answer is:
(i) [C]; (ii) [D]; (iii) [A]; (iv) [B]
(i) [C]
(ii) [D]
(iii) [A]
(iv) [B]
Sol.
(i) – 108.8 eV/a
(ii)54.4 eV/atom
(iii)– 54.4 eV/atom
(iv)13.6 eV/atom
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