According to Bohr’s theory, the electronic energy of hydrogen atom in the nth Bohr orbit is given by
En = 
J Determine the longest wavelength of electron from the third Bohr’s orbit of the He + ion.
Text Solution
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Energy of H-like atom E = E1 × Z2
where, E = Energy of H like atom, i.e., He+ ion
E1 = Energy of H-atom
Z = Atomic number of H-like atom
∴ E = 
× 4 J
To have longest wavelength, the transition would be from n = 3 to n = 4, hence
E3 = 
× 4 J
and, E4 = – 
× 4 J
∴ Δ E = E4 – E3
= 
= –4 × 21.76 × 10–19 
= 4.231 × 10–19 J
Now, Δ E = 
∴ λ = 
= 
= 4.7 × 10–7 m
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