Which the following molecules/species have identical bond order and same magnetic properties ?
(I) O2+ ; (II) NO; (III) N2+
Text Solution
Verified by ExpertsC
(I) O2+ : ( 
1s)2 ( 
*1s)2 ( 
2s)2 ( 
*2s)2 ( 
2pz)2
( 
2p2x = 
2p2y ) ( 
*2px1 = 
*2p0y)
Bond order = 1/2(10 – 5) = 2.5.
(II) NO is derivative of O2 and isoelectronic with O2+ :
so ( 
1s)2 ( 
*1s)2 ( 
2s)2 ( 
*2s)2 ( 
2pz)2
( 
2p2x = 
2p2y ) ( 
*2px1 = 
*2p0y)
Bond order = 1/2(10 – 5) = 2.5.
(III) N2+ : ( 
1s)2 ( 
*1s)2 ( 
2s)2 ( 
*2s)2
( 
2p2x = 
2p2y ) ( 
2pz)1
Bond order = 1/2(9 – 4) = 2.5.
O2+ , NO and N2+ have same bond order i.e. 2.5 and have same magnetic property having one unpaired electron.
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