Match the following
Column I | Column II |
(i) CN– | [A] Bond order is 2, diamagnetic |
(ii) C2 | [B] Bond order is 3, diamagnetic |
(iii) NO | [C] Bond order is 1/2, paramagnetic |
(iv) Ne2+ | [D] Bond order is 5/2, paramagnetic |
Text Solution
Verified by Experts(i) [B]; (ii) [A]; (iii) [D]; (iv) [C]
(i) [B]
(ii) [A]
(iii) [D]
(iv) [C]
Sol.
(i) CN – (6 + 7 + 1 = 14)
σ 1s 2 σ * 1s 2 σ 2s 2 σ* 2s 2 π 2p x 2 π 2p y 2 σ 2p Z 2 B.O. = 
(10 – 4) = 
= 3, Diamagnetic due to absence of unpaired electrons.
(ii) C 2 (12) σ 1s
2 σ * 1s 2 σ 2s 2 σ* 2s 2 π 2px 2 π 2py 2 B.O. = 
(8 – 4) = 
= 2, Diamagnetic
(iii) Bond order is 5/2, paramagnetic
(iv) Bond order is 1/2, paramagnetic
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