Home Chemistry Solution & Colligative Properties General Relative decrease in vapour pressure of an a…
Chemistry Solution & Colligative Properties General Single Correct MCQ
Published on: August 13, 2026

Relative decrease in vapour pressure of an aqueous solution containing 2 moles [Cu(NH3)3 Cl] Cl in 3 moles H2O is 0.50. On reaction with AgNO3, this solution will form(assuming no change in degree of ionisation of substance on adding AgNO3)

A
1 molAgCl
B
0.25 molAgCl
C
0.5 molAgCl
D
0.40 molAgCl

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Text Solution

Verified by Experts
The correct answer is:
C

=

0.5 =

i + 1.5 = 2 i

i = 1.5

i = 1 + (y – 1)

1.5 = 1 + (2 – 1)

= 0.5

mole of Cl– = 1.0

mole of AgCl ppt. = 1.0

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