Two beakers, one containing 20 ml of a 0.05 M aqueous solution of a non volatile, non electrolyte and the other, the same volume of 0.03 M aqueous solution of NaCl, are placed side by side in a closed enclose. What are the volumes in the two beakers when equation is attached ?Volume of the solution in the first and second beaker are respectively.
Text Solution
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Mole of solute in first beaker = 
= 0.001
mole of solute (Na+ & Cl–) in other beaker = 
= 0.0012
conc. of IInd beaker is higher then Ist beaker so water flowes from Ist beaker to IInd beaker till both beaker achieved equal conc. let v volume of water flows from Ist to IInd beaker
so 
v = 1.8 ml
volume of Ist beaker = 20 – 1.8 = 18.2 ml
volume of IInd beaker = 20 + 1.8 = 21.8 ml.
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