The concentration of solutions can be expressed in number of ways such that Normality, Molarity,
Molality, Mole fractions, Strength, % by weight, % by
volume and % by strength. The molarity of ionic
compound is usually expressed as formality because we
use formula weight of ionic compound. Addition of
water to a solution changes all these terms, however
increase in temperature does not change molality, mole
fraction and % by weight terms.
(i) Volume of water required to convert 100 mL 0.5M NaOH solution to 0.2 M NaOH solution is:
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(i)
Sol. Meq. of dil. NaOH = Meq. of conc. NaOH
0.2 × V = 0.5 0 × 100
∴ V = 250 mL
∴ H 2 O needed = 250 – 100 = 150 mL
(ii)
Sol. Al 2 (SO 4 ) 3 + BaCl 2 → BaSO 4 ↓ + AlCl 3
Meq. at 20×0.2×6 20×0.6×2 0 0
t = 0 = 24 = 24 0 0
Meq. after 0 0 24 24
Reaction
∴ [Al 3+ ] = 
= 0.6 N
[Cl – ] = 
= 0.6 N
(iii)
Sol. N NaCl = 
Let w g of BaCl 2 is dissolved in 250 mL then
= 
= 0.0385 w
∴ [Cl – ] in both is same.
∴ N NaCl = 
∴ 0.646 = 0.0385 w
∴ w = 16.80 g
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