The vapour pressure over an aqueous solution (p) containing…

Chemistry Solution & Colligative Properties General Comprehension

Published by: CGP EDU Academic Team

Published on: August 14, 2026

The vapour pressure over an aqueous solution (p)

containing non-volatile solute varies with the mole fraction of the non volatile solute (x 2 ) as follows

p(in torr) = 360 – 100 x 2 – 500 × x 2 2 .

The given solution contain 180 gm water and 0.1 mole solute.

(i) What is the vapour pressure over the solution when x 2 = 0.1 ?

Correct Answers for Comprehension Sub-Questions

Text Solution

Verified by Experts

The correct answer is:

CHECK THE SOLUTION.

(i)

Sol. p = 360 – 10 – 500 × 0.01 = 360 – 10 – 5

= 345 torr

(ii)

Sol. Relative lowering of vap. press = =

= =

(iii)

Sol. As per Raoult's law x 2 = 1, p = 0 and x 2 =0, p =

360

∴ pº – p = x 2 pº

or p = pº – x 2 pº = 360 – 0.1 × 360 = 324

∴ = = = .

(iv)

Sol. p = 360 – 100 x 2 – 500 x 2 2

p = pº – 360 x 2

∴ pº – 360 x 2 = pº – 100 x 2 – 500 x 2 2 or – 260 x 2 = – 500 x 2

2 or x 2 = = 0.72

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