Match the column
Column I | Column II |
(i) 1.2 g of Mg | [A] Hence 10x of solute is Dissolved in 1 ml solution |
(ii) Molarity of chlorine when chlorine gets converted to chloride and chlorate is | [B] One ml of solution weighs 10x g |
(iii) Density of solution is10x g/ml | [C] Reacts with 0.8 g of oxygen to form 2.0 g of MgO. |
(iv) Strength of a solution is 10000 x g in one litre | [D] One sixth of normality. |
Text Solution
Verified by Experts(i) [C]; (ii) [D]; (iii) [B]; (iv) [A]
(i) [C]
(ii) [D]
(iii) [B]
(iv) [A]
Sol.
→ ; 12 g of Mg reacts with 8 g of O 2 to form 20 g of MgO.
⇒ 1.2 g of Mg reacts with 0.8 g of O 2 to form 2.0 g of MgO.
→ ; Cl 2 → Cl – + ClO 3 – ⇒ Cl → Cl
Oxidation state of Cl = 0 in Cl
Oxidation state of Cl in Cl – = – 1
Change in oxidation number = 1
Cl → ClO 3 – [ClO 3 – is chlorate ion]
Oxidation state of Cl in Cl = 0
Oxidation state of Cl in ClO 3 – = 5
⇒ Change in oxidation number = 5
Hence when Cl 2 → Cl – + ClO 3 – Net change in oxidation number is 6.
⇒ Equivalent weight of Cl 2 =
of its molecular weight.
Hence Normality = 6 × Molarity
→ ; Density of solution refers to the mass of the solution which has volume equal to 1ml.
→ ; Strength of solution refers to amount of solute in 1000 ml solution.
Thus if 10000 x g of solute are present in 1000 ml.
⇒ 10 x g of solute are present in 1 ml solution.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems