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CGP EDU Academic Team
Published on: August 13, 2026
1000 gm of 1 (m) sucrose solution in water is cooled to –3.554ºC. What mass of ice would be separated out in nearest possible integers in gm at this temperature ? For water k f = 1.86 K mol –1 kg
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
353
Sol. T f = k f × m
Δ T f = 1.86 × 1 = 1.86
Now, Δ T f = 
1.86 = 
Or 
= 
= 0.342
w + W = 1000
w solute = 254.84 gm
= 745.16 gm.
Δ T = 
= 3.534
or W 1 = 392.18 gm
Therefore amount of ice separated
= W – W 1 = 745.16 – 392.18
= 352.98 gm ~ 353 gm.
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