Published by:
CGP EDU Academic Team
Published on: August 13, 2026
The enthalpy of vapourisation of water = 45.953 
At 1 atm pressure the boiling point of water is 373 K. What is the boiling point of water when pressure equal to 
atm in Kelvin in nearest possible integers ?
Given : log 2 = 0.3
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
356
Sol.
log 
= 
log 
= 
= 2.4 × 10 3 × 
p 2 = 
atm, p 1 = 1 atm
log 
= 2.4 × 10 3 × 
= – log 2
∴ 2.4 × 10 3 × 
= – 0.3
– 
= – 
× 10 –3 = – 0.125 × 10 –3
or 
+ 0.125 × 10 –3 = 
or 
= 2.681 × 10 –3 + 0.125 × 10 –3
= 2.806 × 10 –3 or T 2 = 
= 356.38 K ~ 356 K
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