A compound (lattice I) containing Cd, Sn and P used in the fabrication of some
semiconductors, in which Cd occupying one quarter of the tetrahedral holes and
Sn occupying one half of octahedral holes in the closed packed array of P 3– ions.
The magnetic oxide of cobalt (lattice II) is used in recovering takes in which cobalt ions
at different oxidation states occupying one eighth of the tetrahedral holes and one half of
the octahedral holes in the closed packed array of oxide ions.
In lattice III. A and B atoms are present. A atoms are occupying the corners whereas B
atoms are occupying all the edge centre positions.
(i) What is the molecular formula of the compound as in lattice (I) ?
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(i)
Sol. In the unit cell no. of P 3– = 4
no. of Sn atoms = 2
no. of Cd atoms = 2
∴ m.f is Sn 2 Cd 2 P 4
(ii)
Sol. In the unit cell no. of O 2– ions = 4
Total no. of Co atoms = 1 + 2 = 3
∴ m.f is 
(iii)
Sol.
(iv)
Sol. On the three mutually perpendicular axes neither A atoms nor B atoms are removed. Therefore the m.f of the substance after the defect is AB 3 .
(v)
Sol. The distance between the two B atoms is
= 
= 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems