A mixture of CH 4 and C 2 H 2 occupied a certain volume at a total pressure equal to 63 torr. The same gas mixture was burnt to CO 2 and H 2 O ( λ ). The CO 2 (g) alone was collected in the same volume and at the same temperature, the pressure was found to be 69 torr.
What was the mole fraction of CH 4 in the original gas mixture ?
Text Solution
Verified by ExpertsA
Let no. of moles of CH4 present = n1 mol. Let no. of moles of C2H2 present = n2 mol.
CH4 + 2O2 ⎯→ CO 2 + 2H 2 O n 1 n 1 C2H2 + 
O2 ⎯→ 2 CO 2 + H 2 O n 2 2n 2 Total no. of moles at initial = n 1 + n 2
Total no. of moles at final = n 1 + 2n 2
At constant V & T, 
= 
= 
⇒ 
= 
⇒ 
= 
⇒ 
= 
∴ 
= 
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