Published by:
CGP EDU Academic Team
Published on: August 13, 2026
In a container of volume 1 litre 10 23 gas molecules are present at the r. m. s. speed equal to 10 3 m/s. Determine the total kinetic energies of the gas molecules in kJ in nearest possible integers.
Given : N A = 6 × 10 23 and mass of one molecule = 10 –22 gm
Text Solution
Verified by ExpertsThe correct answer is:
5
Ans. 5
Sol. No. of moles of gas molecules present
= 
= 
.
Mol wt. of gas = 6 × 10 23 × 10 –22 = 60
or u rms = 
= 
or 
= RT
Per mol, KE = 
RT = 
× 
= 
M 
∴ for 
mol, total KE = 
× M × 
× 
= 
× 60 × 10 10 × 
Arg = 5 × 10 3 J = 5 kJ
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