In a reversible chemical reaction, the rate of forward reaction decreases and that of backward reaction increases with the passage of time ; at equilibrium the rate of forward and backward reactions become same. Let us consider the formation of SO 3 (g) in the following reversible reaction: 2SO 2 (g) + O 2 (g) 
2SO 3 (g) Following graphs are plotted for this reactions
(i) In the above graph, A B & C respectively are
Text Solution
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(i)
Sol. Among SO 2 and O 2 initial moles of SO 2 required should be greater.
(ii)
Sol. t 3
(iii)
Sol. At equilibrium r f = r b
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