In phosgene gas reaction, at 400ºC, the initial partial pressures are 
= 342 torr; and 
= 352 torr At 400ºC and at equilibrium total pressure become 440 torr. Now enough N 2 (g) is introduced at equilibrium so that partial pressure of N 2 (g) at new equilibrium become 0.4 atm at 400ºC. Determine percentange increase in the dissociation of COCl 2 (g) at 400ºC due to introduction of N 2 (g) in nearest possible intergers. After introduction of N 2 (g) the total pressure was 1 atm at equilibrium.
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
26%
Sol. CO (g) + Cl 2 (g) 
COCl 2 (g)
Initially: 342 352
At equilibrium: (342 – x) (352 – x)
∴ 342 + 352 – x = 440 = P total
∴ x = 254 torr
∴ 
= 
= 0.334 atm
= 
= 0.116 atm
and 
= 
= 0.128 atm
∴ COCl 2 (g) 
CO (g) + Cl 2 (g)
K p = 
= 
= 4.4 × 10 –2 atm
K p = 
× P
∴ 
= 
= 
= 760 × 10 –4 = 76 × 10 –3 or α = 0.206
After introduction of N 2 (g),
+ 
+ 
= 0.6 atm
and let changed degree of dissociation of COCl 2 (g) = α 1
∴ 
= 4.4 × 10
–2
or α 1 = 0.26
∴ % increase in degree of dissociation of COCl 2
= 
= 26.21 % ~ 26 %
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