Published by:
CGP EDU Academic Team
Published on: August 14, 2026
A mixture of KOH and Ca(OH) 2 weighing 6.13 gram is completely neutralised by an acid. If weight percentage of KOH in mixture is 45.68 and normality of acid is 20N then find the volume (in ml) of acid used in neutralisation.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
7
Sol. wt. of KOH in mixture = 2.80
wt. of Ca(OH) 2 in mixture = 3.33
So 
= V × 10 –3 × 20
⇒ 0.14 = V × 2 × 10 –2 ⇒ V = 
mL = 7 ml
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