Published by:
CGP EDU Academic Team
Published on: August 14, 2026
Given the following data :
Substance | H0 (kJ/mol) | S0(J/mol K) | G0 (kJ/mol) |
FeO(s) | – 266.3 | 57.49 | – 245.12 |
C (Graphite) | 0 | 5.74 | 0 |
Fe(s) | 0 | 27.28 | 0 |
CO(g) | – 110.5 | 197.6 | – 137.15 |
Determine at what temperature the following reaction is spontaneous ?
FeO(s) + C (Graphite) 
Fe(s) + CO(g)
Text Solution
Verified by ExpertsThe correct answer is:
C
G = 
H – T 
S
H = 
H = – 110.5 + 266.3 = 155.8 KJ
S = 
S = 197.6 + 27.28 – (57.5 + 5.74) = 161.64 J/mole K
For reaction to be spontaneous, 
G < 0
H – T 
S < 0 
T > 
= 
= 964 K
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