Published by:
CGP EDU Academic Team
Published on: August 13, 2026
One mole of an ideal diatomic gas (C v = 5cal) was transformed from initial 25°C and 1L to the state when temperature is 100°C and volume 10L. Then for this process (R = 2 Calories/mol/K) (take calories as unit of energy and kelvin for temp )
A
Δ H = 525
B
Δ S = 5 ln 
+ 2 ln 10
+ 2 ln 10
C
Δ E = 525
D
Δ G of the process can not be calculated using given information
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(a, b, d)
Δ S = nC r In 
+ n R In 
Δ H = nC v Δ T ⇒ Δ E = nC v Δ T
⇒ Δ G = Δ H – Δ (TS)
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