Published by:
CGP EDU Academic Team
Published on: August 14, 2026
For reaction A + 2B 
C + D rate law R = k[A] 1 [B] 2 . By what factor would the rate changes if concentration of A is doubled & that of B is halved ?
Text Solution
Verified by ExpertsThe correct answer is:
D
R = k[A] 1 [B] 2
change in rate (2)' 
= 
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