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Chemistry Chemical Kinetics General Single Correct MCQ
Published on: August 14, 2026

Arrhenius studied the effect of temperature on the rate of a reaction and postulated that rate constant varies with temperature exponentially as k = . This method is generally used for finding the activation energy of a reaction. Keeping temperature constant, the effect of catalyst on the activation energy has also been studied. In most of the cases, it is observed that catalyst lowers the activation energy and increases the rate of reaction.

(i) The pre-exponential factor in the Arrhenius equation of a first order reaction has the units –

A
mol L–1 s–1 In k versus T with –ve slope 2 40 kcal mol–1 x = –
B
L mol–1 s–1 k versus 1/T with –ve slope 2.5 12 kcal mol–1 ln x = –
C
s–1 In k versus 1/T with –ve slope 3.0 60 kcal mol–1 x =
D
dimensionless (ii) Which of the following plot will be linear ? In k versus 1/T with +ve slope (iii) If the rate of reaction grows 27 times on increasing the temperature by 30 K, the temperature coefficient of the reaction will be nearly – 3.5 (iv) If the rater reaction doubles for 10ºC rise of temperature from 290 K to 300 K, the activation energy of the reaction will be approximately – 70 kcal mol–1 (v) If x is the fraction of molecules having energy greater than Ea, it will be given by – Any of these

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Text Solution

Verified by Experts
The correct answer is:
C

(i)

Sol. s–1

(ii)

Sol. In k versus 1/T with –ve slope

(iii)

Sol. 3.0

(iv)

Sol. 12 kcal mol–1

(v) Self

Sol. Self

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