Published by:
CGP EDU Academic Team
Published on: August 13, 2026
The rate of a first order reaction increases by 7% when its temperature is raised from 300K to 310K, while its equilibrium constant increases by 3%. Determine the activation energy of the backward reaction in cal in nearest possible integers.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
709
Sol. Given : ln 1.07 = 0.0677 and ln 1.03
= 0.02956
2.303 log 
= 
or 2.303 log 1.07 = 
× 
or 
= (ln 1.07) × 2 × 310 × 30 cal
or 
= 0.0677 × 2 × 310 × 30
= 1259.22 cal
ln 
= 
or ln 1.03 = 
× 
or 0.02956 = 
× 
or Δ H = 549.816 cal
∴ 
= 
– Δ H
= 1259.22 – 549.816
or 
= 709.404 cal
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