Home Chemistry Chemical Kinetics General The rate constant for the first order decomp…
Chemistry Chemical Kinetics General Single Correct MCQ
Published on: August 14, 2026

The rate constant for the first order decomposition of a certain reaction is described by the equation :

log10k (s–1) = 14.3 –

A
What is the energy of activation for this reaction ?
B
At what temperature will its half life period be 256 minutes?

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The correct answer is:
CHECK THE SOLUTION.

Comparing the given equation with

log k = log A –

= 1.25 × 10 4 k

Ea = 2.303R × 1.25 × 10 4 k

= 2.303 × 2 × 10 –3 × 1.25 × 10 4 k cal mol –1

= 57.575 k cal mol –1 = 57575 cal mol

–1 = 240768.28 J mol

–1 = 240.768 k J mol

–1 Now k = = sec

–1 = 4.51 × 10

–5 sec –1 Now from the given relation

log (4.51 × 10

–5 sec –1 ) = 14.34 –

⇒ T = 669 K

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