The standard cell potential 
of a reaction is related as Δ G° = 
, where – Δ G° equals maximum electrical work.
n = number of moles of electrons exchanged as per the balanced chemical equation.
= 
– 
……(i)
and also
= 
……..(ii)
(i) The temperature cofficient of the emf of cell 
is given by –
–4.2 × 10 –4 VK –1 –73.53 JK –1
–3.81 × 10 –4 VK –1 83.53 JK –1
0.11 VK –1 100 JK –1
of the cell is + 7.62 × 10 –4 VK –1 (iii) Calculate Δ S° for the given cell reaction in question number 20 – None of these
Text Solution
Verified by ExpertsB
(i)
Sol. From equation (2)
–nF 
= 
⇒ 
= 
Hence B is correct
(ii)
Sol. Δ H° = –218 KJ, 
= 1.105 V
Substituting from <1>
⎯→
From equ , we have
. 
again from equ. , we have
+ nFE ° = 
(iii)
Sol. Δ H° = –218 KJ mol –1 ∴ 
= – 3.81 × 10
–4 VK –1 And 
= 
Hence is correct
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