Eº RP and their respective half reactions for some
changes are given below :
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(i)
Sol. Mn 2+ (ii)
Sol. Mn
7+ (iii)
Sol. 3Mn
6+ ⎯→ 2Mn 7+ + M 4+ ;
Eº = 
+ 
= – 0.56 + 2.26
= 1.70 V
2Mn 3+ ⎯→ Mn 4+ + Mn 2+ ;
+ 
= – 0.95 + 1.51 = + 0.56 V
(iv)
Sol. E = Eº + 
log 
= + 1.52 + 
= + 1.52 – 1.2272
= 0.2928 V
E = Eº + 
log 
= 2.26 + 
× (–52)
= 2.26 – 1.534
= + 0.726 V
(v)
Sol. Mn 3+ + e ⎯→ Mn 2+ – Δ G 1 º = 1 × 1.51 × F
Mn 4+ + e ⎯→ Mn 3+ – Δ G 2 º = 1 × 0.95 × F
Add Mn 4+ + 2e ⎯→ Mn 2+ ; –( Δ G 1 º + Δ G 2 º)
= (1.51 + 0.95) × F
Also – Δ G 3 º = – ( Δ G 1 º + Δ G 2 º)
2 × E 3 º × F = 2.46 × F E 3 º = 1.23 V
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