Estimate the cell potential of Daniel cell having 1.0 M Zn 2+ and originally having 1.0 M Cu 2+ after sufficient ammonia has been added to the cathode compartment to make the NH 3 concentration 2.0 M. Given 
, 
are 0.76 and – 0.34 V respectively. Also equilibrium constant for the [Cu(NH 3 ) 4 ] 2+ formation is 1 × 10 12 .
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
0.71
Sol.Cu 2+ + 4NH 3 
[Cu(NH 3 ) 4 ] 2+ ∴ K f = 1 × 10
12 = 
= 
x = 6.25 × 10 –14 M
Note that due to high value of K f almost all of the Cu 2+ ions are converted to Cu(NH 3 ) 4 2+ ion.
Now E cell = 
+ 
+ 
log 10 
= 0.76 + 0.34 + 
log 10 
E cell = 0.71 V
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