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CGP EDU Academic Team
Published on: August 14, 2026
10 –2 moles of Fe 3 O 4 is treated with excess of KI solution in presence of dilute H 2 SO 4 , the products are Fe 2+ and I 2 (g). What volume of 0.1 (M) Na 2 S 2 O 3 will be needed to reduce the liberated I 2 (g) ?
Text Solution
Verified by ExpertsThe correct answer is:
C
∴ Fe 3 O 4 + 2I – → Fe 2+ + I 2
∴ no. of moles of I 2 produced = 10 –2 moles
Let v ml 0.1 (M) Na 2 S 2 O 3 solution is required
∴ v × 10 –4 = 2 × 10 –2 or v = 200 ml.
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