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CGP EDU Academic Team
Published on: August 14, 2026
It requires 40 ml of 0.5 (M) Ce 4+ to titrate 10 ml of 1 (M) Sn 2+ where by Sn 2+ is oxidised to Sn 4+ . What is the oxidation state of cerium in the reduction product ?
Text Solution
Verified by ExpertsThe correct answer is:
A
Moles of Ce 4+ reacted = 20 × 10 –3 moles
2 moles of Ce 4+ reacts with ( 4– x) moles of Sn 2+ ∴ 20 × 10
–3 moles of Ce 4+ reacts with
( 4– x) × 10 –2 moles of Sn 2+ ∴ (4 – x) × 10
–2 = 10 × 10 –3 ∴ 4 – x = 1
or x = + 3.
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