Given:
AgCl(s) + 2NH 3
Ag(NH 3 ) 2 + + Cl – Kº = 2.79 × 10 –3 AgCl(s)+2NH 4 OH
Ag(NH 3 ) 2
+ + Cl – + 2H 2 O
Kº = 8.46 × 10 –7 (i) The solubility of AgCl(s) in 1(M) NH 3 is about
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(i)
Sol. AgCl(s) + 2NH 3
Ag(NH 3 ) 2 + + Cl –
s s
= 2.79 × 10 –3 = 27.9 × 10 –4 s = 5.28 × 10
–2 (M) ~ 0.053 (M)
(ii)
Sol. AgCl(s) + 2NH 4 OH 
Ag(NH 3 ) 2 + + Cl – + 2H 2 O
s s
∴
= 8.46 × 10 –7 or s =
× 10
–4 = 9.19 × 10 –4 (M) ~ 9.2 × 0 –4 (M)
(iii)
Sol. Let equilibrium constant for the reaction
NH 3 + H 2 O
NH 4 OH is K
∴ K 2 =
× 10 7 × 2.79 × 10 –3 = 10 4 × 0.33 or K = 57.43
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