Published by:
CGP EDU Academic Team
Published on: August 14, 2026
The coordination number and the oxidations state of the element E in the complex.
(where (en) is ethylene diamine are, repectively)
Text Solution
Verified by ExpertsThe correct answer is:
A
In the given complex
ethylene diamine is a bidentate ligand and
oxalate ion is also bidentate ligand. Therefore co-ordinations number of the complex is 6 i.e., it is an octahedral complex. Oxidations number of E in the given complex is
x + 2 × 0+ 1 × (-2) = +1

Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Copper sulphate dissolves in ammonia due ot the formations of
The number of ions give by in aqueous solutions will be
Which of the following ligands forms a chelate?
Which of the following is not a neutral ligand?
Which of the following ligands will not show chelation?
The complex ion which has no -electrons in the central metal atom is