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CGP EDU Academic Team
Published on: August 13, 2026
The coordination number and the oxidation state of the element 'E' in the complex [E(en)2(C2O4)] NO2 (when 'en' is ethylene diamine) are, respectively,
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Verified by ExpertsThe correct answer is:
C
Let oxidation state of E is x so x + (–2) + 0 = +1 or x = +3 Coordination number is number of s-bonds between metal ion and ligands. 'en' and 'ox' are bidentate ligands Thus ; coordination number of E = 4 + 2 = 6.
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