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Published on: August 13, 2026
HC ≡ C–CH 2 –CH=CH 2 , adds up HBr to give HC ≡ C–CH 2 –CHBr–CH 3 while CH ≡ C–CH=CH 2 adds up HBr to give CH 2 =CH.Br.CH=CH 2
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An isolated double bond is more reactive than an isolated triple bond towards electrophilic addition and thus
HC ≡ C–CH 2 –CH=CH 2 + HBr ⎯→
CH ≡ C–CH 2 –CHBr–CH 3
On the other hand , in second case formation of
conjugated diene takes place if triple bond is attacked. The conjugated dienes are more stable than alkyne
CH 2 =CH–C ≡ CH + HBr ⎯→
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