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CGP EDU Academic Team
Published on: August 13, 2026
When SO 2 is passed through acidified K 2 Cr 2 O 7 solution :
Text Solution
Verified by ExpertsThe correct answer is:
C
K 2 Cr 2 O 7 + 4H 2 SO 4 — → K 2 SO 4 + Cr 2 (SO 4 ) 3 + 4H 2 O + 3O
[SO 2 + [O] + H 2 O — → H 2 SO 4 × 3.
K 2 Cr 2 O 7 + H 2 SO 4 + 3SO 2 — → K 2 SO 4 + Cr 2 (SO 4 ) 3 (Green coloured) + 3H 2 O
Acidified K 2 Cr 2 O 7 is oxidising agent and undergoes reduction to form green coloured solution of Cr 2 (SO 4 ) 3.
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