Published by:
CGP EDU Academic Team
Published on: August 12, 2026
S 2– and S 32– can be distinguished by using :
Text Solution
Verified by ExpertsThe correct answer is:
C
S 2– + (CH 3 COO) 2 Pb — → PbS ↓ + 2CH 3 COO –
black ppt.
S 2– + Na 2 [Fe(CN) 5 NO] — → [Fe(CN) 5 NOS] 4– + 2Na +
violet ppt.
Hence, they are distinguished by both the reagents as only S 2– gives precipitate with these reagents.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
In the separation of Cu 2+ and Cd 2+ in 2 nd group qualitative analysis of cations, tetrammine copp…
The metal ion which is precipitated when H 2 S is passed with HCl :
In boraxs bead test which compound is formed ?
When H 2 S gas is passed in a metal sulphate solution in presence of NH 4 OH, a white precipitate i…
H 2 S gas when passed through a solution of cations containing HCl precipitates the cations of seco…
HgCl 2 and I 2 both when dissolved in water containing I – ions the pair of species formed is