Published by:
CGP EDU Academic Team
Published on: August 11, 2026
In electrolysis of Al 2 O 3 by Hall-Heroult process :
Text Solution
Verified by ExpertsThe correct answer is:
C
Na 3 [AlF 6 ] — → 3NaF + AlF 3
NaF and AlF 3 both are ionic compounds and so ionise to give ions. This increases the electrical conductivity and lowers the melting point of Al 2 O 3 .
At cathode : Al 3+ (melt) + 3e – — → Al.
At anode : C(s) + O 2– (melt) — → CO (g) + 2e – ; C(s) + 2O 2– (melt) — → CO 2 (g) + 4e – .
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