Pick out the incorrect statement.
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N 2 : ( σ 1s) 2 ( σ *1s) 2 ( σ 2s) 2 ( σ *2s) 2 ( π 2p2x = π 2p2y ) (σ 2pz) 2
The bond order of N 2 is 1/2(10 – 4) = 3.
N 2+ : ( σ 1s) 2 ( σ *1s) 2 ( σ 2s) 2 ( σ *2s) 2 ( π 2p2x = π 2p2y ) (σ 2pz) 1
The bond order of N 2+ is 1/2(9 – 4) = 2.5.
O 2 : ( σ 1s) 2 ( σ *1s) 2 ( σ 2s) 2 ( σ *2s) 2 ( σ 2pz) 2 ( π 2p2x = π 2p2y ) ( π *2px1 = π *2p1y)
The bond order of O 2 1/2(10 – 6) = 2.
O 2– : ( σ 1s) 2 ( σ *1s) 2 ( σ 2s) 2 ( σ *2s) 2 ( σ 2pz) 2 ( π 2p2x = π 2p2y ) ( π *2px2 = π *2p1y)
The bond order of O 2 1/2(10 – 7) = 1.5.
NO + derivative of O 2 and isoelectronic with O 22+ ; so ( σ 1s) 2 ( σ *1s) 2 ( σ 2s) 2 ( σ *2s) 2 (σ 2pz) 2 ( π 2p2x = π 2p2y )
The bond order of NO+ 1/2(10 – 4) = 3.
NO derivative of O 2 and isoelectronic with O 2+ ; ( σ 1s) 2 ( σ *1s)2 ( σ 2s) 2 ( σ *2s) 2 (σ 2pz) 2 ( π 2p2x = π 2p2y ), (π *2px) 1
The bond order of NO is 1/2(10 – 5) = 2.5.
bond order 1/bond length ∝ bond dissociation energy.
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