Published by:
CGP EDU Academic Team
Published on: August 13, 2026
2.5 g of protein containing only glycine (C 2 H 5 NO 2 ) is dissolved in water to make 500 mL of solution. The osmotic pressure of this solution at 300 K is found to be 5.03 x 10 -3 bar. The total number of glycine units present in the protein is____ (Given : R = 0.083 L bar K -1 mol -1 )
Text Solution
Verified by ExpertsThe correct answer is:
330
(330)
= CRT
5.03 x10 -3 = Cx0.083x300
C = 0.202 x10 -3 M
Moles of protein = 0.202 x 10 -3 x 0.5
= 10 -4 x1.01
1.01x10 -4 = 
M(molar mass of protein) = 24752
No. of glycine units = 
= 330.03
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