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CGP EDU Academic Team
Published on: August 13, 2026
50 mL of 0.1 M CH 3 COOH is being titrated against 0.1 M NaOH. When 25 mL of NaOH has been added, the pH of the solution will be ________x 10 -2 . (Nearest integer) (Given : pK a (CH 3 COOH) = 4.76) log 2 = 0.30
Text Solution
Verified by ExpertsThe correct answer is:
476
(476)
Moles of CH 3 COOH = 5 m
mole moles of NaOH = 2.5 m
mole NaOH + CH 3 COOH 
CH 3 COONa + H 2 O
2.5 m mole 2.5 m mole
0 2.5m mole 2.5m mole
so buffer is formed
pH=4.76
=476x10 -2
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