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CGP EDU Academic Team
Published on: August 13, 2026
1.2 mL of acetic acid is dissolved in water to make 2.0 L of solution. The depression in freezing point observed for this strength of acid is 0.0198°C. The percentage of dissociation of the acid is________.(Nearest integer)[Given : Density of acetic acid is 1.02 g mL -1 Molar mass of acetic acid is 60 g mol -1 K f (H 2 O)=1.85Kkgmol -1 ]
Text Solution
Verified by ExpertsThe correct answer is:
5
(5)
M = dxV=1.02x1.2 = 1.224gm
Moles of acetic acid = 0.0204 moles in 2L
So molality = 0.0102 mol/kg
Now 
T f = i x K f x M
i = 1 + 
for acetic acid
0.0198 = (1 + 
) x 1.85x0.0102
= 0.04928
5%
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