Given below are two statements :
Statement I: [Ni(CN)4] 2- is square planar and diamagnetic complex, with dsp 2 hybridization for Ni but [Ni(CO) 4 ] is tetrahedral. paramagnetic and with sp 3 -hybridication for Ni.
Statement II: [NiCl 4 ] 2- and [Ni(CO) 4 ] both have same d-electron configuration have same geometry and are paramagnetic.
choose the correct answer form the options given below:
Text Solution
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[Ni(CN) 4 ] 2- : d 8 configuration, SFL, sq. planar splitting (dsp 2 ), diamagnetic.
[Ni(CO) 4 ] : d 10 config (after excitation), SFL, tetrahedral splitting (sp 3 ), diamagnetic.
[NiCl 4 ] 2- : d 8 config, WFL, tetrahedral splitting (sp 3 ), paramagnetic (2 unpaired e - ).
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