Number of complex(es) which will exist in cis-trans is/are

Chemistry Co-ordinatios Compounds JEE Main 2022 Single Correct MCQ

Published by: CGP EDU Academic Team

Published on: August 12, 2026

CoCl 3 .4NH 3

CoCl 3 .5NH 3

CoCl 3 .6NH 3 and

CoCl(NO 3 ) 2 .5NH 3

Text Solution

Verified by Experts

The correct answer is:

CoCl 3 .4NH 3 = [Co(NH 3 ) 4 C1 2 ]C1

Can exhibit G.I.

CoCl 3 .5NH 3 = [Co(NH 3 ) 5 C1]C1 2

Can't exhibit G.I.

CoCl 3 .6NH 3 = [Co(NH 3 ) 6 ]Cl 3

Can't exhibit G.I.

CoCl(NO 3 ) 2 -5NH 3 = [Co(NH 3 ) 5 C1](NO 3 ) 2

= [Co(NH 3 ) 5 (N0 3 )]Cl(NO 3 )

Both can't exhibit G.I.

Previous Question Next Question

Get practice questions, solutions, and test series in one place.

Share your experience with this question and solution.

Send your comment, doubt, correction, or feedback to admin.

What students say about this solution

No reviews yet. Be the first to write a review.